tag:blogger.com,1999:blog-6847048658257278783.post3847443114101308580..comments2024-03-29T01:36:12.851+00:00Comments on Guitar FX Layouts: Seymour Duncan Pickup BoosterIvIarkhttp://www.blogger.com/profile/08416945174853142251noreply@blogger.comBlogger73125tag:blogger.com,1999:blog-6847048658257278783.post-82112959292997171172019-03-06T11:57:56.948+00:002019-03-06T11:57:56.948+00:00Hello I built it but there is a little boost maybe...Hello I built it but there is a little boost maybe a fault and I am not an expert.q1 9-4-4v q2 9-4-4v q3 9-9-4v is this right?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-60456245396445710872018-12-18T14:58:08.945+00:002018-12-18T14:58:08.945+00:00very simple circuitvery simple circuitguru elektronik 13https://www.blogger.com/profile/10732141827126932129noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-85658305751501359732016-11-14T08:33:08.784+00:002016-11-14T08:33:08.784+00:00hello, here is my build of this pedal
http://hpics...hello, here is my build of this pedal<br />http://hpics.li/c003e5a<br />http://hpics.li/730a8e8<br /><br />this is my first build, but I am quite happy with he result.<br />I use it between my guitar and my tube amp (Kustom defender) and it really takes it to a new level of distortion that I was waiting for.<br /><br />The case is a cooking device from French army. The knob comes from an old tube radio receiver, and the light comes from a new old stock I got.Anonymoushttps://www.blogger.com/profile/07591269721577398603noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-83585410649560004512016-08-05T06:24:28.597+01:002016-08-05T06:24:28.597+01:00I wired the B500k pot backwards to get my way arou...I wired the B500k pot backwards to get my way around the "C" pot taper type , the decibel issue as in going from 3 to 25db instead of 6db to 25db. <br /><br />but would i do with a push pull to get it to work. Anonymoushttps://www.blogger.com/profile/02073372949146969805noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-7174812075801342122016-08-05T06:12:11.718+01:002016-08-05T06:12:11.718+01:00This comment has been removed by the author.Anonymoushttps://www.blogger.com/profile/02073372949146969805noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-22764180719367166522016-08-05T06:11:00.751+01:002016-08-05T06:11:00.751+01:00so say I wanted to put this into a guitar. I'm...so say I wanted to put this into a guitar. I'm using a B500k push pull. I used a 51k metal film resistor and soldered the outer lugs giving me the resistance of approximately 45k to "solve" the decibel issue. <br /><br />However I'm having a hard time wrapping my head around the last little bit. How would I be able to switch the battery on and off. It's an onboard preamp I'm trying for. I tried the "true bypass" method below which I know it makes no sense considering this pedal is better as a buffer but as we can tell I'm really new to this. <br /><br />the top method of 'true bypass" i went for<br />http://www.muzique.com/schem/dpdt.gif<br /><br />so I get my guitars sound properly , all the connections are fine. That is when I pull up on the push pull. <br /><br />when i have it down I get no sound at all. <br /><br />should I just have the switch for the battery on and off? or what would you guys do. Anonymoushttps://www.blogger.com/profile/02073372949146969805noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-51773311192950903512016-04-25T10:46:12.316+01:002016-04-25T10:46:12.316+01:00Hey! somebody here said that minimal 6db of boost ...Hey! somebody here said that minimal 6db of boost is to much for him. But what if we just change boost pot on link and add master volume pot after output of circuit? if my idea is correct it will be same boost pedal but with opportunity of any wanted level of volume. what do you think about that idea?DerPrhttps://www.blogger.com/profile/02955026993994574587noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-43028328032913018252015-02-07T18:26:20.711+00:002015-02-07T18:26:20.711+00:00Ok great!
But now...
i have BC177, BC177A and BC17...Ok great!<br />But now...<br />i have BC177, BC177A and BC177B<br />and also BC107A and BC107B<br /><br />What do you suggest?<br />I know that i should socket and try...but i'm putting the circuit onboard my stratocaster, under the pickguard, and trying it's too hard..<br /><br />:(VVPhttps://www.blogger.com/profile/15862716599287800546noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-84064328403601481162015-02-07T18:23:44.677+00:002015-02-07T18:23:44.677+00:00This comment has been removed by the author.VVPhttps://www.blogger.com/profile/15862716599287800546noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-32058872935104686422015-02-05T13:23:18.692+00:002015-02-05T13:23:18.692+00:00i would solder a 50k resistor between lugs 1 and 3...i would solder a 50k resistor between lugs 1 and 3 to make it kinda 25k pot. 50k pot might distort after 12 o'clock settings.ξεναγός νεκρόποληςhttps://www.blogger.com/profile/13463939372683232133noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-33738957033874628372015-02-04T18:33:45.036+00:002015-02-04T18:33:45.036+00:00ehy guys...50k pot should works good?
thanks.ehy guys...50k pot should works good?<br />thanks.VVPhttps://www.blogger.com/profile/15862716599287800546noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-75477110476872769492014-11-26T09:38:58.185+00:002014-11-26T09:38:58.185+00:00Thanks once again, Mirosol. I'll give it a tr...Thanks once again, Mirosol. I'll give it a try.MJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-21820783584720201352014-11-26T09:36:53.986+00:002014-11-26T09:36:53.986+00:00Thanks to everyone. I must be too dense to grasp t...Thanks to everyone. I must be too dense to grasp the concept of CBE. Everyone can't be wrong, right? It must be me.<br /><br />I had my say and I think that everything productive and positive has been explored.<br /><br />I apologize if I have injected static into the forum. It wasn't my intent.<br /><br />Everything is good.MJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-84753931479266896982014-11-26T09:34:54.329+00:002014-11-26T09:34:54.329+00:00It is rather small circuit, so building it isn'...It is rather small circuit, so building it isn't too big of a task. That way you could see it works for yourself.<br /><br />App:<br />https://code.google.com/p/diy-layout-creator/<br /><br />+mmirosolhttps://www.blogger.com/profile/02400327798106357876noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-80137348682956403422014-11-26T09:18:10.971+00:002014-11-26T09:18:10.971+00:00Yes you're getting too hung up on the transist...Yes you're getting too hung up on the transistor graphic. The notes say that Q1 and Q2 are BC107's which are round metal can transistors and don't match the layout, but it suggests trying BC550's (and BC560s for Q3) which would be inserted exactly as shown in the layout. Q1 and Q2 with flat side to the left makes the pin out C, B and E from top to bottom as shown in the layout. Q3 with the flat side to the right makes it E, B and C from top to bottom, again exactly as shown in the layout.<br /><br />The orientation of the transistors is always going to depend on what you use. If you used 2N5088's instead then the transistors would all need rotating 180 degrees to those shown in the layout. But again as Miro and Travis have both said, it's the pin out that is important so make sure that matches the order shown in the layout no matter what you use.IvIarkhttps://www.blogger.com/profile/08416945174853142251noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-73839565416257978122014-11-26T09:13:26.558+00:002014-11-26T09:13:26.558+00:00Miro,
I bow to your expertise although I still ca...Miro,<br /><br />I bow to your expertise although I still can't see it. If you have checked it and are satisfied, then we're good.<br /><br />If I may ask, what software are you using for your Vero layouts? I've looked around the site, but didn't see any posts.<br /><br />TIAMJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-84433936377771522862014-11-26T09:05:21.522+00:002014-11-26T09:05:21.522+00:00I'm sorry to tell you but you are wrong and yo...I'm sorry to tell you but you are wrong and you have been all the way. Just look at the layout and look at the schematic. On both, Q1 has 30K between its collector and supply, right? On both, Q1 has 30K between its emitter and ground, right? On both, Q2 has its collector to supply, right? Emitter of Q2 is connected to Q1 emitter and thus, via 30K to ground, right? Emitter of Q3 is connected to supply, right? Layout has to match the schematic for it to work. If you are convinced that the layout is in error, then the Analogguru's schematic has to be in error.<br /><br />You should probably stop using pin numbers from transistor leads as they vary between 2N and BC models and are not standard. Just use the names - base, collector and emitter.<br /><br />And no. I've built this circuit twice with TO92 transistors...<br />+mmirosolhttps://www.blogger.com/profile/02400327798106357876noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-55249756260815021382014-11-26T08:45:46.357+00:002014-11-26T08:45:46.357+00:00Miro,
Yes, unless I'm crazy. Q1 and Q2 need ...Miro,<br /><br />Yes, unless I'm crazy. Q1 and Q2 need to be turned around to face the same way as Q3. Then, their pin 1 (collector) will then be connected to +V.<br /><br />I'm pretty sure at this point, but you need to sanity check me, of course.<br /><br />Maybe the best course would be to swap out the TO92 packages for TO18s if possible. I am guessing that when everyone built the boards they used TO18 parts and thus didn't detect the orientation.<br /><br />Of course, I could still be wrong. You be the judge.<br /><br />Many thanks again for all your work. It is impressive and much appreciated.MJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-22207170565070688952014-11-26T07:55:39.666+00:002014-11-26T07:55:39.666+00:00So you're suggesting the vero and schematic do...So you're suggesting the vero and schematic do not match each other?<br />+mmirosolhttps://www.blogger.com/profile/02400327798106357876noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-71173449416302061812014-11-26T05:10:30.783+00:002014-11-26T05:10:30.783+00:00Aha! You are looking at the schematic and I am lo...Aha! You are looking at the schematic and I am looking at the diagram of the Vero board.<br /><br />Hehehe!MJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-16545587704311618052014-11-26T05:05:00.067+00:002014-11-26T05:05:00.067+00:00It seems like you're caught up on the orientat...It seems like you're caught up on the orientation of the transistor symbol, when the only thing you need to pay attention to are the C, B, and E locations<br /><br />Whether the transistor is CBE or EBC is irrelevant. Just insert it so that the collector goes to C, base to B, and emitter to ETravishttps://www.blogger.com/profile/00836791717229314419noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-39687855732967547292014-11-26T04:07:45.637+00:002014-11-26T04:07:45.637+00:00Travis,
If the top pin of Q1 and Q2 are collector...Travis,<br /><br />If the top pin of Q1 and Q2 are collectors, then doesn't that make the pinout EBC and not CBE? <br /><br />I couldn't find a BC107 pinout for the TO92 package. However, the BC548, which is a plastic TO-92 equivalent of the BC107 according to Wiki, is a CBE.<br /><br />I am starting to think that Q1 and Q2 are reversed. Of course, it's hard to believe that this didn't get caught when folks built the circuit, so I still might be bonkers.<br /><br />Please take a look and let me know...<br /><br />MJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-72855389688692650042014-11-26T03:48:57.259+00:002014-11-26T03:48:57.259+00:00The top pin of Q2 and Q1 are the collectors. They&...The top pin of Q2 and Q1 are the collectors. They're labelled C. Q2 collector is tied directly to 9V, and the emitters of both Q1 and Q2 are tied to ground through a 33K resistor<br /><br />Q3 is the only one that's "backwards" (because it's PNP) as Mark and Miro explained Travishttps://www.blogger.com/profile/00836791717229314419noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-82568570202838840572014-11-25T22:34:04.519+00:002014-11-25T22:34:04.519+00:00This is getting Kafkaesque! In the diagram, the t...This is getting Kafkaesque! In the diagram, the topmost pin of Q2 should be pin 3, yes? If the transistor is CBE, then the topmost pin is the Emitter, yes? It is tied to +9V, yes?<br /><br />I know I am missing something. Everybody can't be wrong.<br /><br />Thanks for all your time.MJGhttps://www.blogger.com/profile/11435050999775166036noreply@blogger.comtag:blogger.com,1999:blog-6847048658257278783.post-91721606941029033942014-11-25T14:50:33.248+00:002014-11-25T14:50:33.248+00:00"In the diagram, Q1 and Q2 are NPN transistor..."In the diagram, Q1 and Q2 are NPN transistors with a pinout of CBE, but then <br /><br />pin 3 (the emitter) of Q2 is tied directly to +9V."<br /><br />Q3 emitter is tied to 9v, Q2 collector is tied to 9v and Q1 collector connects to 9v via 30k resistor.dexxyyhttps://www.blogger.com/profile/15083992477248920480noreply@blogger.com